From owner-biophysics@net.bio.net Sun Nov 02 22:00:00 1997
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From: Yu Wai Chen <ywc@mrc-lmb.cam.ac.uk>
Newsgroups: bionet.molbio.methds-reagnts,bionet.biophysics
Subject: Site-directed spin labelling
Date: Mon, 03 Nov 1997 10:56:58 +0000
Organization: MRC Centre for Protein Engineering
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Dear All,

I am trying to introduce a spin probe by reaction at a
site-directed-mutated cysteine residue of a GST-fusion protein.  If this
protein forms aggregate on cleavage of the GST, does anyone has any
experience about how to label it?  Shall I label it in its GST-fusion
soluble form and then cleave off the GST or shall I cut off the GST
first and then label the aggregate?  Thanks.

-- 
===================================================================
Yu Wai CHEN, Ph.D. ..................  email: ywc@mrc-lmb.cam.ac.uk
 Centre for Protein Engineering,              tel: 44-(1223) 402148
 MRC Centre, Cambridge  CB2 2QH, U.K.         fax: 44-(1223) 402140
 WWW homepage: http://www.mrc-cpe.cam.ac.uk/people/wai.html

From owner-biophysics@net.bio.net Wed Nov 05 22:00:00 1997
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From: prismx@earthlink.net (Claire Haller)
Newsgroups: bionet.neuroscience,bionet.biophysics,bionet.cellbiol,bionet.general,sci.misc
Subject: SCIENCE-WEEK: This Week's Headlines (7 Nov 97)
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Xref: biosci bionet.neuroscience:20681 bionet.biophysics:3657 bionet.cellbiol:8376 bionet.general:28613

Headlines for the current SCIENCE-WEEK (November 7, 1997)

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13. Lack of Correlation of DDT Levels with Breast Cancer Risk

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From owner-biophysics@net.bio.net Wed Nov 05 22:00:00 1997
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From: propdig <thomreg@barryinc.com>
Newsgroups: bionet.biophysics
Subject: National Biotech Register(NatBio) New Service
Date: Thu, 06 Nov 1997 09:57:07 -0500
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From owner-biophysics@net.bio.net Thu Nov 06 22:00:00 1997
Path: biosci!musc.edu!vakseri
From: vakseri@musc.edu (Ilya Vakser)
Newsgroups: bionet.biophysics
Subject: Postdocs/Graduate Students in Protein Docking and Structure Prediction
Date: 7 Nov 1997 14:28:28 -0800
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From owner-biophysics@net.bio.net Sat Nov 08 22:00:00 1997
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From: aaa@no-spam.tutoraid.org (Academic Assistance Access)
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Subject: Do you academic need help in PHYSICS ?
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From owner-biophysics@net.bio.net Sun Nov 09 22:00:00 1997
Path: biosci!news.ohsu.edu!not-for-mail
From: Matt Jones <jonesmat@ohsu.edu>
Newsgroups: bionet.biophysics
Subject: Re: entropy.
Date: 10 Nov 1997 22:39:29 GMT
Organization: Vollum Institute
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In article <647tcn$drs@ds2.acs.ucalgary.ca> Walter L. Ash,
ash1@freenet.calgary.ab.ca writes:
>He's convinced
>that
>life reverses the trend by organizing matter and energy whereas I'm
>convinced that more organized forms of energy are eventually turned
>into the random motion of heat by the chemical processes occuring in
>cells...

You are absolutely right, and your friend is wrong. In fact, your
friend's argument (not that he means it this way) is often used by
creationists and like-minded people to support the notion that there must
be a God. 

The creationist argument goes something like this: 
Life is more ordered than non-life, which is chaotic. Since physics says
everything must tend towards disorder, but life doesn't do that, life
violates the laws of physics. Anything that violates the laws of physics
is a miracle. Miracles come from God. Therefore, the existence of life
proves that there is a God.

I'm sure God is breathing a big sigh of relief, knowing that creationists
have finally proven His/Her existence ;->

But the main flaw in the argument is that physics doesn't say that every
"thing" tends towards entropy, it says that the entropy of the whole
universe put together can't get any smaller than it is now. Little parts
of it can, otherwise ice wouldn't form, we would have no salt for our
french fries, nor would we be around to eat them. 

Another flaw is that life is _not_ more ordered than, for example, rocks,
salt, ice, etc, and so has no special claim on divine intervention.  

You can look this stuff up in _any_ physics book with a chapter on
thermodynamics of chemical reactions. You don't need a special biophysics
book, because it's the same physics all around. Aristotle (in
Metaphysics, I think) actually spent whole chapters on the subject "How
is Man different from a rock?". Not a simple question to answer, actually.

Cheers,

Matt

From owner-biophysics@net.bio.net Sun Nov 09 22:00:00 1997
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From: "Walter L. Ash" <ash1@freenet.calgary.ab.ca>
Newsgroups: bionet.biophysics
Subject: entropy.
Date: Mon, 10 Nov 1997 14:12:44 -0700
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   A friend and I were recently debating whether or not the systems in the
universe we call "organisms" decreased the overall entropy of the
universe, or increased it. Somewhere
I had heard or read that even though in the specific area the system
exists entropy is decreased, the overall entropy of the universe is
increased by the chemical processes of life within a cell or organism.
My overall understanding is that no matter how complex life may become
our universe as a whole will still move towards entropy; perhapsthe
process is even accelerated by the workings of life.  He's convinced
that
life reverses the trend by organizing matter and energy whereas I'm
convinced that more organized forms of energy are eventually turned
into the random motion of heat by the chemical processes occuring in
cells... I
couldn't find my textbooks to look it up so I was wondering if anyone here
could offer any insight into entropy and life's effect on it.  



From owner-biophysics@net.bio.net Sun Nov 09 22:00:00 1997
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From: Marc Roussel <roussel@henri.chem.uleth.ca>
Newsgroups: bionet.biophysics
Subject: Re: entropy.
Date: Mon, 10 Nov 1997 15:19:57 -0700
Organization: Department of Chemistry and Biochemistry, University of Lethbridge
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To: "Walter L. Ash" <ash1@freenet.calgary.ab.ca>

Walter L. Ash wrote:
>A friend and I were recently debating whether or not the systems in the
> universe we call "organisms" decreased the overall entropy of the
> universe, or increased it.
[...]
> I couldn't find my textbooks to look it up so I was wondering if
> anyone here could offer any insight into entropy and life's effect on
> it.

     As far as we know, the second law of thermodynamics is never
violated.  However, you have to be careful about how you interpret the
second law.  Here is the second law in its most general form:

     The entropy of an adiabatic system never decreases.

"Adiabatic" means that the system is perfectly thermally insulated or,
in other words, that heat can't enter or escape it.  As far as we know,
the Universe is an adiabatic system (where would the heat go?) so the
entropy of the Universe can't decrease.
     Living organisms on the other hand are about as far from being
adiabatic systems as you can imagine.  They're not even closed!  (They
exchange matter with their surroundings.)  Living organisms therefore
don't satisfy any naive version of the second law.  They do satisfy the
second law, but you have to include their effect on the rest of the
Universe.  Here's a semi-mathematical paraphrase of a version of the
second law which does apply to living organisms:

	(change in entropy of organism)
			+
	(change in entropy of rest of Universe due to organism)

	is a positive quantity.

The entropy of the organism and its immediate surroundings can decrease
PROVIDED the entropy of the rest of the Universe increases more.  The
short answer then is that you were right.
     It's possible to make these ideas a great deal more rigorous
through nonequilibrium thermodynamics.  (Because they are open systems,
living organisms pose a number of challenges to classical thermodynamics
which was designed mainly to deal with steam engines and other
relatively simple machines.)  The version of the second law used there
suggests that living organisms must produce entropy, which is
essentially what I said above.

				Marc R. Roussel
				(roussel@uleth.ca)
				Department of Chemistry and Biochemistry
				University of Lethbridge

From owner-biophysics@net.bio.net Mon Nov 10 22:00:00 1997
Path: biosci!rutgers!nntp.upenn.edu!dsinc!news.voicenet.com!europa.clark.net!192.174.65.44!newscore.univie.ac.at!news.iif.hu!szia
From: szia@hanga.enzim.hu (Andras Szilagyi)
Newsgroups: bionet.biophysics
Subject: Re: entropy.
Date: 11 Nov 1997 00:48:44 GMT
Organization: IIF
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On 10 Nov 1997 22:39:29 GMT, Matt Jones <jonesmat@ohsu.edu> wrote:

>But the main flaw in the argument is that physics doesn't say that every
>"thing" tends towards entropy, it says that the entropy of the whole
>universe put together can't get any smaller than it is now.

What physics says is that the entropy of an _isolated system_ won't
decrease. Whether the universe is an isolated system can be a matter of
debate. It is usually considered as an isolated system by definition, for
convenience. However, this is rather speculative.

Andras Szilagyi


From owner-biophysics@net.bio.net Mon Nov 10 22:00:00 1997
Path: biosci!HOTMAIL.COM!computerphys
From: computerphys@HOTMAIL.COM
Newsgroups: bionet.biophysics
Subject: Best kept "secrets" finally exposed
                                                                  
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Date: 11 Nov 1997 06:28:53 -0800
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From owner-biophysics@net.bio.net Mon Nov 10 22:00:00 1997
Path: biosci!bloom-beacon.mit.edu!senator-bedfellow.mit.edu!usenet
From: "David F. Green" <dfgreen@lms.mit.edu>
Newsgroups: bionet.biophysics
Subject: Re: entropy.
Date: Mon, 10 Nov 1997 21:32:10 -0500
Organization: Massachusetts Institute of Technology
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You are correct that the entropy of the universe always increases. 
While life is highly organized and thus represents a local region of low
entropy, the energy expended by life to maintain this highly ordered
state ultimately results in a greater increase in the entropy of its
surroundings (i.e. the universe other than the organism).  That the
entropy of the universe (system plus surroundings) must always increase
is one of the fundamental laws of thermodynamics.  Thus for any process
in which the entropy of a system decreases, the entropy of the
surroundings must increase by a greater amount.

-- 
************************************************
David F. Green
Department of Chemistry
Massachusetts Institute of Technology
Cambridge, MA 02139

E-mail: dfgreen@lms.mit.edu
Phone: (617) 228-6229
************************************************

From owner-biophysics@net.bio.net Mon Nov 10 22:00:00 1997
Path: biosci!news.ohsu.edu!not-for-mail
From: Matt Jones <jonesmat@ohsu.edu>
Newsgroups: bionet.biophysics
Subject: Re: entropy.
Date: 11 Nov 1997 22:08:46 GMT
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In article <slrn66hjjn.epn.szia@hanga.enzim.hu> Andras Szilagyi,
szia@hanga.enzim.hu writes:
>Are you sure? Consider the number of microstates realizing a living
>organism versus the number of microstates realizing a rock. I think that
>the latter must be a great deal larger. I think that a living organism is
>much more farther from equilibrium than a rock is. They can be definitely
>distinguished from each other thermodynamically.

I'm not sure I follow you. If by "microstates" you "mean degrees of
freedom" in the sense used in statistical mechanics (or information
theory) then whichever has the largest number of microstates would be the
_less_ ordered system. Are you saying that a rock has more degrees of
freedom than an organism? Generally, crystals are used as an example of
extremely ordered systems. 

Another thing: Being far from equilibrium is not the only thing important
in deciding whether something is more complex or less ordered than
something else. The sun is very, very far from equilibrium in a strictly
thermodynamic sense. Much farther than any living thing. Is it more
complex? Is it more ordered? I'd say it's probably less complex than an
amoeba and more ordered than a bacterium, but less ordered than a
crystalized virus. One can in fact freeze living cells indefinitely, and
then thaw them out and they go on dividing etc, as if nothing had ever
happened. Do they stop being alive while they are frozen?

Cheers,

Matt

From owner-biophysics@net.bio.net Mon Nov 10 22:00:00 1997
Path: biosci!agate!hammer.uoregon.edu!logbridge.uoregon.edu!newsfeed.ecrc.net!newscore.univie.ac.at!news.iif.hu!szia
From: szia@hanga.enzim.hu (Andras Szilagyi)
Newsgroups: bionet.biophysics
Subject: Re: entropy.
Date: 11 Nov 1997 21:26:23 GMT
Organization: IIF
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On 10 Nov 1997 22:39:29 GMT, Matt Jones <jonesmat@ohsu.edu> wrote:

>Another flaw is that life is _not_ more ordered than, for example, rocks,
>salt, ice, etc, [...]

Are you sure? Consider the number of microstates realizing a living
organism versus the number of microstates realizing a rock. I think that
the latter must be a great deal larger. I think that a living organism is
much more farther from equilibrium than a rock is. They can be definitely
distinguished from each other thermodynamically.

(This is not to say that divine intervention is necessary to create a
living organism. Nonequilibrium thermodynamics can account for the
appearence of organized complexity in systems subject to a flow of
energy.)

Andras Szilagyi


From owner-biophysics@net.bio.net Mon Nov 10 22:00:00 1997
Path: biosci!news.ohsu.edu!not-for-mail
From: Matt Jones <jonesmat@ohsu.edu>
Newsgroups: bionet.biophysics
Subject: Beer Theories
Date: 11 Nov 1997 20:03:52 GMT
Organization: Vollum Institute
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X-XXDate: Tue, 11 Nov 1997 20:10:59 GMT

Hi all,

Here's a subject that comes up between myself and colleagues often enough
to warrant some serious thought. Maybe this is more of a chemistry
question, but since I usually end up discussing it with biophysicists in
the pub, I'll post it here.

When you open a bottle of beer, bubbles form. Is this purely a physical
reaction (i.e., no covalent bonds being made or broken), or does it
involve a chemical transformation? 

Any takers?

Matt

From owner-biophysics@net.bio.net Mon Nov 10 22:00:00 1997
Path: biosci!news.ohsu.edu!not-for-mail
From: Matt Jones <jonesmat@ohsu.edu>
Newsgroups: bionet.biophysics
Subject: Re: entropy.
Date: 11 Nov 1997 19:59:09 GMT
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In article <01IPVPM7X0D000007I@buphyc.bu.edu> Bernard Chasan,
bc@BUPHYC.BU.EDU writes:
>  In his ardor to remove any need for divine intervention Matt
>overstates the case . A living organism differs significantly from a rock
>in its ability, produced by evolution, to maintain, at least  for a while,
>its status as an open system, far from equilibrium. Rocks have not
>developed enzymes. Rocks don't have the ability to use the incoming solar
>energy flux in highly specialized ways. Rocks don't export entropy into
>their surroundings. For that matter, rocks don't replicate .
> Matt, and other interested readers, would do well to read Schrodinger's essay,
>"What is Life ?"

Hi Bernard,

Your points are well taken and thank you for suggesting the Scrodinger
essay. 

However, let me clarify: I am not interested in removing the need for
divine intervention. My personal belief is that the universe is a product
of divine fiat. But that's my own personal belief. As a scientist, I
don't like it when people construct arguments about God (or anything
else, for that matter) that are so terribly flawed as to be totally
nonsensical. I don't think such arguments are useful, and they tend to
spread misinformation which doesn't help anybody except the person making
the argument, who probably has a social, moral or political agenda rather
than a scientific one. 

Now for some fun (the following is intended in the spirit of playful,
half-serious debate):

You said: 
>A living organism differs significantly from a rock
>in its ability, produced by evolution, to maintain, at least  for a while,
>its status as an open system, far from equilibrium.

The ocean is an open system far from equilibrium. Is it alive?

As for rocks,
First, geologists (of which I am not one) commonly use the term
"evolution" in refering to the formation of rocks. There are actually a
lot of complicated reactions that go into producing your average rock,
and these reactions take a long time and are subject to things in the
environment like temperature, pressure, the earth's magnetic field, even
biological activity which produces atmospheric oxygen etc. There _are_
selective pressures on whether a certain rock's chemistry will be stable
or unstable in its environment, and whether it will survive in that form
or be chemically changed into a different rock. So rocks evolve.

Second, Rocks haven't evolved enzymes, true. But rocks contain structures
that can catalyze chemical reactions.  You can even get some high school
chem lab experiments to work faster by tossing in a few pebbles, which
presumably provide a large crenulated surface area that somehow helps the
reactants to come together. I think this is also why the bubbles in a
beer glass always seem to form on the side of the glass instead of in the
middle of the beer (ooh, this could be the start of a whole new thread).
These catalytic structures just don't happen to be biological proteins,
but that is a minor point.

Third, until recently people didn't "have the ability to use the incoming
solar
energy flux in highly specialized ways" either. Were they therefore not
alive?

Fourth, after sitting in the sun for a while, rocks absolutely _do_
export entropy into their surroundings during the night. That's why the
asphalt steams in the morning after a summer rain.

Fifth, rocks don't replicate? Hmm. What's crystallization if not the
replication of crystals? One crystal serves as a nucleating center for
further crystal outgrowth. You can break off chunks of a crystal and look
at one, and find that it contains little tiny replicas of the parent
crystal. A chip off the old block, as it were.

Sixth, Schrodinger postulated that the structure of DNA was an aperiodic
crystal. An aperiodic crystal sounds like a rock to me.

So, in conclusion:
Why is Man different from a rock? Beats me ;-)

Cheers,

Matt


"You block! You stone! You worse than senseless thing!"
-From the Epic of Gilgamesh

From owner-biophysics@net.bio.net Mon Nov 10 22:00:00 1997
Path: biosci!daresbury!not-for-mail
From: <RUMYM@BGEARN.ACAD.BG>
Newsgroups: bionet.biophysics
Subject: entropy (Pentcho Valev)
Date: 11 Nov 1997 16:20:22 -0000
Lines: 40
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Original-To: biophys@dl.ac.uk

(This message may appear twice - sorry about that).

That, for a spontaneous process, the entropy change of the system plus
the environment is always positive, is a tautology - it would be the same
to say "A spontaneous process is a spontaneous process". In chemistry
and biology this statement about the entropy is transformed into "For a
spontaneous process, the free energy change is always negative". So let me
prove that this last statement is just a tautology.
   Let us consider the following spontaneous reaction:

        A  ->  B                                           /1/

Spontaneity consists in the fact that

        Vf > Vr                                            /2/

where Vf and Vr are the velocities of the forward and reverse reaction.
Therefore

      Kf(A)  >  Kr(B)                                        /3/

where Kf and Kr are the respective rate constants and ( ) is concentration.
Further

       Kf/Kr  >  (B)/(A)                                    /4/

By taking ln and multiplying by RT we obtain

      0  >  -RTlnK  +  RTln((B)/(A))                      /5/

where K = Kf/Kr is the equilibrium constant, i.e. we obtain

      0  >  delta Go  +  RTln((B)/(A)  =  delta G            /6/

   Therefore, /6/ follows from and is tautologous to /2/. This means
that /6/ is always correct, even if the second law is not.


Pentcho Valev


From owner-biophysics@net.bio.net Mon Nov 10 22:00:00 1997
Path: biosci!BUPHYC.BU.EDU!bc
From: bc@BUPHYC.BU.EDU (Bernard Chasan)
Newsgroups: bionet.biophysics
Subject: Re: entropy.
Date: 11 Nov 1997 07:47:52 -0800
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>You can look this stuff up in _any_ physics book with a chapter on
>thermodynamics of chemical reactions. You don't need a special biophysics
>book, because it's the same physics all around. Aristotle (in
>Metaphysics, I think) actually spent whole chapters on the subject "How
>is Man different from a rock?". Not a simple question to answer, actually.
>
>Cheers,
>
>Matt
  In his ardor to remove any need for divine intervention Matt
overstates the case . A living organism differs significantly from a rock
in its ability, produced by evolution, to maintain, at least  for a while,
its status as an open system, far from equilibrium. Rocks have not
developed enzymes. Rocks don't have the ability to use the incoming solar
energy flux in highly specialized ways. Rocks don't export entropy into
their surroundings. For that matter, rocks don't replicate .
 Matt, and other interested readers, would do well to read Schrodinger's essay,
"What is Life ?"


Professor Bernard Chasan
Physics Department, Boston University
 Boston MA 02215
(617) 353-2608



From owner-biophysics@net.bio.net Mon Nov 10 22:00:00 1997
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From: <computerphys@hotmail.com>
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Subject: Best kept "secrets" finally exposed
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From owner-biophysics@net.bio.net Tue Nov 11 22:00:00 1997
Path: biosci!daresbury!not-for-mail
From: <RUMYM@BGEARN.ACAD.BG>
Newsgroups: bionet.biophysics
Subject: entropy (Pentcho Valev)
Date: 12 Nov 1997 10:22:11 -0000
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Original-To: biophys@dl.ac.uk

(Again, sorry for writing my name in the subject space).

That, for a spontaneous process, the entropy change of the system plus
the environment is always positive, is a tautology - it would be the same
to say "A spontaneous process is a spontaneous process". In chemistry
and biology this statement about the entropy is transformed into "For a
spontaneous process, the free energy change is always negative". So let me
prove that this last statement is just a tautology.
   Let us consider the following spontaneous reaction:

        A  ->  B                                           /1/

Spontaneity consists in the fact that

        Vf > Vr                                            /2/

where Vf and Vr are the velocities of the forward and reverse reaction.
Therefore

      Kf(A)  >  Kr(B)                                        /3/

where Kf and Kr are the respective rate constants and ( ) is concentration.
Further

       Kf/Kr  >  (B)/(A)                                    /4/

By taking ln and multiplying by RT we obtain

      0  >  -RTlnK  +  RTln((B)/(A))                      /5/

where K = Kf/Kr is the equilibrium constant, i.e. we obtain

      0  >  delta Go  +  RTln((B)/(A)  =  delta G            /6/

   Therefore, /6/ follows from and is tautologous to /2/. This means
that /6/ is always correct, even if the second law is not.


Pentcho Valev


From owner-biophysics@net.bio.net Tue Nov 11 22:00:00 1997
Message-ID: <34696381.167E@came.sbg.ac.at>
Date: Wed, 12 Nov 1997 09:06:25 +0100
From: Walter Koppensteiner <walter@came.sbg.ac.at>
Organization: Center for Applied Molecular Engineering
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Subject: Re: Beer Theories
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Matt Jones wrote:
> When you open a bottle of beer, bubbles form. Is this purely a physical
> reaction (i.e., no covalent bonds being made or broken), or does it
> involve a chemical transformation?

Carbondioxide which is solved in water react with it:
    _    
HCO3  + H+   <--->  CO2 + H2O

The equilibrium of this reaction lies on the side of CO2 but
can be shifted to the left side if the system is under
pressure (a consequence of simple chemical thermodynamics).

If you open a beer bottle the equilibrium is shifted to
the right side and CO2 bubbles form.

Hope this helps,
Walter
-- 
===============================================================
Walter Koppensteiner                                           
                                            
University of Salzburg
Center of Applied Molecular Engineering

Jakob Haringer Strasse 3           Phone: +43-662-8044-5794
A-5020 Salzburg, Austria           Fax:   +43-662-454889
                                   Email: walter@came.sbg.ac.at
===============================================================

From owner-biophysics@net.bio.net Tue Nov 11 22:00:00 1997
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From: jamesl@healthtech.com (James W. Larkin)
Newsgroups: bionet.biophysics,bionet.molbio.proteins.fluorescent,sci.chem.electrochem
Subject: Call for Papers Advances in MOLECULAR LABELS, SIGNALING & DETECTION
Date: 12 Nov 1997 12:51:23 GMT
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Xref: biosci bionet.biophysics:3677 bionet.molbio.proteins.fluorescent:1728

First Announcement and Call for Papers

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Advances in MOLECULAR LABELS, SIGNALING & DETECTION: 
Enhancing Sensitivity, Accuracy and Speed
May 4-5, 1998
San Diego Hilton

Extending the limits of assay sensitivity and accuracy, at the same 
time meeting the demand for greater speed, requires the application 
of innovative techniques and systems.  The development of new probes 
and labels, homogeneous assay designs, and approaches which allow 
for the direct detection of compounds or specific binding events are 
having an impact in basic research, diagnostic and drug development 
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critical for the implementation of greater speed and automation.  
These advances are being applied to the detection, quantification 
and localization of gene sequences, proteins, infectious organisms 
and a variety of other targets.

Researchers are encouraged to submit a proposal  for presentation of 
their own work.  Recommendations for other speakers to be considered 
are also welcomed.  Among the topics to be covered are:

Novel Probes and Labels
New Homogeneous Assays
Methods for Direct (Non-amplified) Quantitation
Methods for Ultra-Sensitive Detection
Novel Fluorescent Assay Systems
New Luminescent Approaches

Please submit proposal or suggestions by e-mail or fax to:

Mary Chitty
Conference Director
e-mail:  mchitty@healthtech.com
fax:      617-630-1325
telephone: 617-630-1316

For full consideration and to allow time for followup, please submit 
proposal or suggestions by December 1, 1997.


From owner-biophysics@net.bio.net Tue Nov 11 22:00:00 1997
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From: Marc Roussel <roussel@henri.chem.uleth.ca>
Newsgroups: bionet.biophysics
Subject: Re: entropy (Pentcho Valev)
Date: Wed, 12 Nov 1997 12:18:46 -0700
Organization: Department of Chemistry and Biochemistry, University of Lethbridge
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RUMYM@BGEARN.ACAD.BG wrote:
> That, for a spontaneous process, the entropy change of the system plus
> the environment is always positive, is a tautology
[...]
>       0  >  delta Go  +  RTln((B)/(A)  =  delta G            /6/
> 
>    Therefore, /6/ follows from and is tautologous to /2/. This means
> that /6/ is always correct, even if the second law is not.

Delta G = Delta G0 + RT ln(Q) is not a fact independent of the second
law.  Furthermore, using Delta G can only be used as a criterion of
spontaneity under particular conditions (constant T and P).  The second
law is much more general than that.

				Marc R. Roussel
				(roussel@uleth.ca)
				Department of Chemistry and Biochemistry
				University of Lethbridge

From owner-biophysics@net.bio.net Tue Nov 11 22:00:00 1997
Path: biosci!news.ohsu.edu!not-for-mail
From: Matt Jones <jonesmat@ohsu.edu>
Newsgroups: bionet.biophysics
Subject: Re: entropy.
Date: 12 Nov 1997 17:26:36 GMT
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In article <slrn66j99q.ghd.szia@hanga.enzim.hu> Andras Szilagyi,
szia@hanga.enzim.hu writes:
>Excuse me if my English is not perfect.

It's perfect, as far as I can tell.

>Please define what you mean by "orderedness".
>What I was speaking about was entropy, which is defined in statistical
>mechanics as k*ln(Y) where k is the Boltzmann factor and Y is the number
>of microstates that make up the given macrostate."

Yeah, that's what I meant too, except .

>I think that your notion of orderedness is not directly related to
>entropy, what the subject of this thread is.

Nonetheless spatial ordering, as in a crystal, and entropy are intimately
related concepts. For example, one formulation of the third law is the
following (from Molecular Thermodynamics, Dickerson, 1969):

"The entropy for all pure, crystalline, perfectly ordered substances at
absolute zero is zero."

This defines an absolute entropy scale based on the spatial ordering of
components. Thus, in a "perfectly ordered" crystal, all "microstates" are
indistinguishable. An organism therefore must have a higher entropy than
such a crystal. Granted, rocks aren't perfect crystals, but they still
have lower entropy than an organism because a lot of the microstates are
indistinguishable (due to the semi-periodic arrangement of atoms). 

Cheers,

Matt

From owner-biophysics@net.bio.net Tue Nov 11 22:00:00 1997
Path: biosci!daresbury!not-for-mail
From: <RUMYM@BGEARN.ACAD.BG>
Newsgroups: bionet.biophysics
Subject: The second law problem (Pentcho Valev)
Date: 12 Nov 1997 14:33:56 -0000
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I must admit that my previous message was somewhat enigmatic - in fact, I
do not like this typical thermodynamic approach - formally everything is
OK but one feels that the truth has remained hidden. So, although I
realize that my claims would never be accepted by experts - the conflict of
interest is enormous, I still find it suitable to elaborate on the problem -
maybe some non-experts would follow the logical line to the end. In the
distant future, this might prove rather useful for science.

   The basic formulation of the second law is a statement about HEAT and
WORK. This means that both heat and work are ALREADY defined, and we are
to apply or verify the statement in different contexts. This is exactly
the case, for instance, when we deal with the Carnot machine. The work an
ideal gas does is defined prior to and independently of the second law, so
nobody can doubt any version of the second law in this case.

   However this is not the case in chemistry. CHEMICAL WORK is not defined
prior to and independently of the second law. On the contrary, it is
defined AD HOC - the delta G concept in fact says: "Chemical work is what
the second law says it is". Here begins the tautologous vicious circle -
the second law cannot be violated BY DEFINITION - any work done is, by
definition, just as much as needed to satisfy the second law.

Fortunately, there are cases in which chemical systems do other types of
work - e.g. electrical one. This breaks the vicious circle at
places. In galvanic systems, for instance, the work done DOES satisfy
the second law (if reversible, it is equal to the negative of delta G).
However no generalization should be made - this is macroscopic work and
the process is closer to gas expansion than to a genuine chemical reaction.

So we urgenly need at least one more verification. Everything else is
a hidden tautology - nothing can  disprove the second law so far as
the basic concept - WORK, is defined so as to make any disproval impossible.
Of course, the problem is much more complicated than that - I still hope
that hostility will end and the discussion will clarify even the most
dark corners of the theory.

Best regards,
Pentcho

From owner-biophysics@net.bio.net Tue Nov 11 22:00:00 1997
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From: szia@hanga.enzim.hu (Andras Szilagyi)
Newsgroups: bionet.biophysics
Subject: Re: entropy.
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On 11 Nov 1997 22:08:46 GMT, Matt Jones <jonesmat@ohsu.edu> wrote:

>I'm not sure I follow you. If by "microstates" you "mean degrees of
>freedom" in the sense used in statistical mechanics (or information
>theory) then whichever has the largest number of microstates would be the
>_less_ ordered system. Are you saying that a rock has more degrees of
>freedom than an organism? Generally, crystals are used as an example of
>extremely ordered systems. 

Please define what you mean by "orderedness".

What I was speaking about was entropy, which is defined in statistical
mechanics as k*ln(Y) where k is the Boltzmann factor and Y is the number
of microstates that make up the given macrostate.

That is, what we should compare is the number of ways you can arrange the
atoms of a rock to obtain a rock vs. the number of ways you can arrange
the atoms of a living organism to obtain that living organism. I'm saying
that the latter is much smaller than the first, therefore the entropy of
a living organism is smaller than that of a rock (given they have the
same number of atoms). If you throw a number of atoms together in a
random arrangement then it is much more probable that you will end up
with a rock (or a crystal for that matter) than that you will end up with
a living organism.

I think your notion of orderedness has more to do with periodicity in
space but that does not necessarily mean a state of very low entropy. You
can replace any unit cell in a crystal by another unit cell and the
crystal will remain the same. Actually you can make up a crystal from its
unit cells in an extremely large number of ways. A living organism is
different: you can't replace a neuron by a liver cell or the like.

Thus, I think that your notion of orderedness is not directly related to
entropy, what the subject of this thread is. Complexity, however, seems
to be directly related to entropy: the more complex a system is the more
information is required to create that system from its components, and,
consequently, the less is the entropy of the system (as information is
actually negative entropy, as we know from information theory).

Excuse me if my English is not perfect.

Andras Szilagyi


From owner-biophysics@net.bio.net Wed Nov 12 22:00:00 1997
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From owner-biophysics@net.bio.net Wed Nov 12 22:00:00 1997
Path: biosci!daresbury!not-for-mail
From: <RUMYM@BGEARN.ACAD.BG>
Newsgroups: bionet.biophysics
Subject: entropy (Pentcho Valev)
Date: 13 Nov 1997 09:27:28 -0000
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Marc Roussel wrote:
Delta G = Delta G0 + RT ln(Q) is not a fact independent of the second<
law.  Furthermore, using Delta G can only be used as a criterion of<
spontaneity under particular conditions (constant T and P).  The second<
law is much more general than that.<

Marc, I believe I have proved the following two things:

1. If the second law is correct, delta G for a spontaneous reaction, at
constant T and P, is negative.

2. If the second law is not correct, delta G for a spontaneous reaction,
at constant T and P, is also negative.

Please tell me whether you accept these two statements. If not, what in
my proof do you find wrong? If yes, would you mind if I describe the
implications? They are very interesting.


Best regards,
Pentcho

From owner-biophysics@net.bio.net Wed Nov 12 22:00:00 1997
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From: Don Bashford <bashford@gage.scripps.edu>
Newsgroups: bionet.biophysics
Subject: Re: entropy.
Date: 13 Nov 1997 00:06:06 -0800
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szia@hanga.enzim.hu (Andras Szilagyi) writes:

> That is, what we should compare is the number of ways you can arrange the
> atoms of a rock to obtain a rock vs. the number of ways you can arrange
> the atoms of a living organism to obtain that living organism....

Not fair!  You allow the rock's atoms any arrangement the forms "A rock",
while the organism's atoms must form "THAT living organism".  It's as
if you want to compare a one-gram insect with with a gram of some
freely morphing "rock" system that is actually an equilibrium ensemble of all
possible "rocks" composed of a given number and type of atoms.

How about comparing a one-gram insect with a single one-gram crystal?

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From owner-biophysics@net.bio.net Wed Nov 12 22:00:00 1997
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From: <RUMYM@BGEARN.ACAD.BG>
Newsgroups: bionet.biophysics
Subject: Boltzmann's and thermodynamic entropy do not coincide (Pentcho)
Date: 13 Nov 1997 16:03:25 -0000
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In reply to Andras Szilagyi

I will base my proof on
interesting chemical models called semigrand ensembles (Robert
Alberty, Legendre Transforms in Chemical Thermodynamics, Chemical Reviews,
1994, Vol. 94, No 6, p. 1463). Here is one of them:


         I            I               I

         I            I               I

         I---------piston-------------I

         I                            I

         Imembrane permeable only to DI

         I                            I

         I      A + B = C + D         I

         I----------------------------I

    One of the walls of the chamber in which the gas reaction A + B = C + D
occurs is a membrane permeable only to D, and there is a piston behind the
membrane. The reaction is strongly exothermic so that, in a REVERSIBLE
ISOTHERMAL expansion of D, heat is released by the system. (In other words,
the exothermic heat is greater than the work done as the piston is pushed).
   It follows directly from the last assumption that, as the reaction
proceeds, the thermodynamic entropy of the system DECREASES. (This still
does not violate the second law - the entropy of the surroundings increases
of course). On the other hand, this course of the reaction (comprising
expansion of D) can also be spontaneous, i.e. it is a movement towards
a more probable state - Boltzmann's entropy INCREASES.
   I hope the proof is obvious and satisfactory.

Pentcho

From owner-biophysics@net.bio.net Wed Nov 12 22:00:00 1997
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From: szia@hanga.enzim.hu (Andras Szilagyi)
Newsgroups: bionet.biophysics
Subject: Re: rock - living organism comparison  (Pentcho Valev)
Date: 13 Nov 1997 14:27:55 GMT
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On 13 Nov 1997 10:35:32 -0000, RUMYM@BGEARN.ACAD.BG
<RUMYM@BGEARN.ACAD.BG> wrote:

>As you are speaking of the entropy of complex systems, do you mean the
>Boltzmann entropy (proportional to the ln of probability), or the
>thermodynamic entropy (defined by dQ/T)? The two do not coincide -
>there are systems for which one can be shown to increase and the other
>to decrease.

Please prove that.

Andras Szilagyi


From owner-biophysics@net.bio.net Wed Nov 12 22:00:00 1997
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From: szia@hanga.enzim.hu (Andras Szilagyi)
Newsgroups: bionet.biophysics
Subject: Re: entropy.
Date: 13 Nov 1997 14:25:19 GMT
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On 12 Nov 1997 17:26:36 GMT, Matt Jones <jonesmat@ohsu.edu> wrote:

>Nonetheless spatial ordering, as in a crystal, and entropy are intimately
>related concepts. For example, one formulation of the third law is the
>following (from Molecular Thermodynamics, Dickerson, 1969):
>
>"The entropy for all pure, crystalline, perfectly ordered substances at
>absolute zero is zero."
>
>This defines an absolute entropy scale based on the spatial ordering of
>components.

This is true for almost everything, not only crystals but living
organisms too (probably they will crystallize at T=0). At T=0, S=0 for
all substances, with some interesting exceptions.

But what about higher temperatures? That at T=0, S=0 does not say
anything about how S increases with T and which substance will have
higher entropy at T=300K for example.

You did not react to my arguments about the relationship of entropy and
complexity (and information). Do you agree that more information is
needed to describe a living organism than a crystal? If yes, then the
entropy of the crystal will be higher because information is negative
entropy.

Something is wrong with the reasoning of one of us :-)

>Thus, in a "perfectly ordered" crystal, all "microstates" are
>indistinguishable.

S=0 only if Y=1. (Y is the number of microscopic states.) In that case,
there is only one single microstate so you actually can't say "all
microstates are indistinguishable".

Andras


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Don Bashford wrote in message ...
>szia@hanga.enzim.hu (Andras Szilagyi) writes:
>
>> That is, what we should compare is the number of ways you can arrange
the
>> atoms of a rock to obtain a rock vs. the number of ways you can
arrange
>> the atoms of a living organism to obtain that living organism....
>
>Not fair!  You allow the rock's atoms any arrangement the forms "A
rock",
>while the organism's atoms must form "THAT living organism".  It's as
>if you want to compare a one-gram insect with with a gram of some
>freely morphing "rock" system that is actually an equilibrium ensemble
of all
>possible "rocks" composed of a given number and type of atoms.
>
>How about comparing a one-gram insect with a single one-gram crystal?

I think this misses the point. The rock is not amorphous, but
crystalline i.e. order
begins on a microscale. In contrast, much of an organism is totally
amorphous.
Let's just take those 5 litres of blood in the human body and consider
the
possible microstates which are still compatible with it remaining blood!
I would
bet that this is orders of magnitude higher than the possible
microstates
which can form in an equivalent mass of rock




From owner-biophysics@net.bio.net Wed Nov 12 22:00:00 1997
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From: <RUMYM@BGEARN.ACAD.BG>
Newsgroups: bionet.biophysics
Subject: rock - living organism comparison  (Pentcho Valev)
Date: 13 Nov 1997 10:35:32 -0000
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As you are speaking of the entropy of complex systems, do you mean the
Boltzmann entropy (proportional to the ln of probability), or the
thermodynamic entropy (defined by dQ/T)? The two do not coincide -
there are systems for which one can be shown to increase and the other
to decrease.

Best regards,
Pentcho Valev

From owner-biophysics@net.bio.net Wed Nov 12 22:00:00 1997
Path: biosci!daresbury!not-for-mail
From: <RUMYM@BGEARN.ACAD.BG>
Newsgroups: bionet.biophysics
Subject: entropy (Pentcho Valev)
Date: 13 Nov 1997 09:30:18 -0000
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Marc Roussel wrote:
Delta G = Delta G0 + RT ln(Q) is not a fact independent of the second<
law.  Furthermore, using Delta G can only be used as a criterion of<
spontaneity under particular conditions (constant T and P).  The second<
law is much more general than that.<

Marc, I believe I have proved the following two things:

1. If the second law is correct, delta G for a spontaneous reaction, at
constant T and P, is negative.

2. If the second law is not correct, delta G for a spontaneous reaction,
at constant T and P, is also negative.

Please tell me whether you accept these two statements. If not, what in
my proof do you find wrong? If yes, would you mind if I describe the
implications? They are very interesting.


Best regards,
Pentcho

From owner-biophysics@net.bio.net Wed Nov 12 22:00:00 1997
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From: fujimoto@u.washington.edu (Bryant Fujimoto)
Newsgroups: bionet.biophysics
Subject: Re: Boltzmann's and thermodynamic entropy do not coincide (Pentcho)
Date: 13 Nov 1997 21:23:03 GMT
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<RUMYM@BGEARN.ACAD.BG> writes:

>In reply to Andras Szilagyi

>I will base my proof on
>interesting chemical models called semigrand ensembles (Robert
>Alberty, Legendre Transforms in Chemical Thermodynamics, Chemical Reviews,
>1994, Vol. 94, No 6, p. 1463). Here is one of them:


>         I            I               I

>         I            I               I

>         I---------piston-------------I

>         I                            I

>         Imembrane permeable only to DI

>         I                            I

>         I      A + B = C + D         I

>         I----------------------------I

>    One of the walls of the chamber in which the gas reaction A + B = C + D
>occurs is a membrane permeable only to D, and there is a piston behind the
>membrane. The reaction is strongly exothermic so that, in a REVERSIBLE
>ISOTHERMAL expansion of D, heat is released by the system. (In other words,
>the exothermic heat is greater than the work done as the piston is pushed).
>   It follows directly from the last assumption that, as the reaction
>proceeds, the thermodynamic entropy of the system DECREASES. (This still
>does not violate the second law - the entropy of the surroundings increases
>of course). On the other hand, this course of the reaction (comprising
>expansion of D) can also be spontaneous, i.e. it is a movement towards
>a more probable state - Boltzmann's entropy INCREASES.
>   I hope the proof is obvious and satisfactory.

Pentcho
  Your initial condition involves some (unstated) initial concentrations
of the reactants and products.  As the piston behind the membrane is
moved back, the reaction proceeds to products, and D leaves the reaction
chamber.  At the end, the reaction chamber will contain C and only a
very small quantity of D.  Are you really sure the entropy of the
reaction chamber hasn't gone down?  
  The problem is that you haven't given any details.  What are
A, B, C and D?  What are the initial and final concentrations?  Just how
much heat leaves the reaction chamber?  (Are you sure you understand
what reversible means in the context of the second law?)
  One more thing, it is possible to determine the entropy of a system
at temperature T if you know the heat capacity at constant pressure as a
function of temperature from near 0K to T, and also Delta H for any
phase transitions between 0K and T.  This isn't known for many systems,
but for the few that it is, the calcuation can be down and it agrees to
within experimental error with the results of statistical mechanics.

Bryant Fujimoto
fujimoto@u.washington.edu

From owner-biophysics@net.bio.net Wed Nov 12 22:00:00 1997
Path: biosci!news.ohsu.edu!not-for-mail
From: Matt Jones <jonesmat@ohsu.edu>
Newsgroups: bionet.biophysics
Subject: Re: Beer Theories
Date: 13 Nov 1997 18:19:38 GMT
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In article <34696381.167E@came.sbg.ac.at> Walter Koppensteiner,
walter@came.sbg.ac.at writes:
>Carbondioxide which is solved in water react with it:
>    _    
>HCO3  + H+   <--->  CO2 + H2O
>
>The equilibrium of this reaction lies on the side of CO2 but
>can be shifted to the left side if the system is under
>pressure (a consequence of simple chemical thermodynamics).
>
>If you open a beer bottle the equilibrium is shifted to
>the right side and CO2 bubbles form.
>

I've gotten several responses to this question so far, by email and
through this group.
So far, there are two classes of responses: About half of the responses
said that carbon dioxide was dissolved in solution and formed bubbles
when you relieved the pressure, with no chemical reaction at all. The
others said the carbon dioxide is produced in response to a change in
pressure. This explanation is concisely stated in the quote above, and
seems likely to be most accurate.

Now, two accompanying questions (we'll get to the bottom of this pint
yet!):

1)	Why are there bubbles at all? Why doesn't the CO2 just stay equally
distributed throughout the solution?

And finally:

2)	Why do the bubbles form on the glass surfaces, instead of just
spontaneoulsy occuring anywhere in solution (you may need to crack open a
frosty one and experiment to prove to yourself that this is actually the
case. Go ahaead, I'll wait.)?

Cheers,

Matt Jones

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Subject: Re: entropy.
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In article <slrn66m3n1.lkv.szia@hanga.enzim.hu> Andras Szilagyi,
szia@hanga.enzim.hu writes:
>Something is wrong with the reasoning of one of us :-)

It might well be my reasoning that's wrong, but I'm not ready to give up
yet ;-)

>This is true for almost everything, not only crystals but living
>organisms too (probably they will crystallize at T=0). At T=0, S=0 for
>all substances, with some interesting exceptions.

Respectfully, no. It's a well known problem in biology that not
everything crystallizes into a well ordered form. A perfect example is
the attempt to derive three-dimensional structures of proteins from x-ray
diffraction through protein crystals. This works for a lot of proteins
quite well, but there are whole families of proteins for which it doesn't
work at all (so far, but that may change). There are no crystal
structures known for membrane proteins such as neurotransmitter-gated ion
channels because of this very reason. So the exceptions are far more
numerous than not. That is why the law has to be formulated to include
the phrases "pure" and "perfectly ordered crystalline" etc.

>But what about higher temperatures? That at T=0, S=0 does not say
>anything about how S increases with T and which substance will have
>higher entropy at T=300K for example.

That's true. But would you be willing to accept that a liquid has more
microstates than a solid of the same number of atoms? If so, then a cell
is more liquid than a rock, and therefore has more microstates. Now, of
course, it's the probability of achieving a particular set of microstates
out of the total possible number that one uses in entropy calculations,
so the question boils down to exactly what you talked about earlier: How
many different ways are there of arranging all the atoms to get an
organism, how many ways are there of getting a rock, and how many total
combinations are there all together (let's assume were dealing with
exactly the same atoms). I'd say that this is not a perfectly
straightforward question because there are _a lot_ of different ways of
getting an organism from the same atoms. One can conceivably build either
an amoeba or a neuron, for example. Also, if one builds an amoeba, it can
wiggle around and change it's shape and all that, so there are clearly _a
lot_ (perhaps an infinite) of ways of getting an amoeba from the same
atoms. One might say the same thing about a rock, I suppose. So as far as
I can tell, it's not clear just from this argument, that one has a higher
or lower entropy than the other.

>S=0 only if Y=1. (Y is the number of microscopic states.) In that case,
>there is only one single microstate so you actually can't say "all
>microstates are indistinguishable".

Well, this is sort of a philisophical issue. How many electrons are there
in the universe? We can't tell two electrons apart from each other
(because an electron is 100% defined in terms of it's properties, so
they're all the same). There could be a lot of electrons, or there could
just be one that runs around really quickly and participates in every
atomic orbital in existence (like Santa Claus ;-). Either way, you're
right, Y=1. But I say it's because there's no way to distinguish two or
more (hypothetically) different versions.

Now, the critical point which I didn't respond to last time:

>You did not react to my arguments about the relationship of entropy and
>complexity (and information). Do you agree that more information is
>needed to describe a living organism than a crystal? If yes, then the
>entropy of the crystal will be higher because information is negative
>entropy.

This is a tough one. We are used to thinking of living things as being
sooo complex that we can't possibly understand them. Oh, if only we had
enough information, then we would understand life! Obviously, this
reflects your (quite reasonable) point of view that one needs more
"information" to describe an amoeba than table salt. So, information
theory would seem the logical choice for trying to quantify biological
"information" content, and would use a function very similar to the
statistical mechanics definition of entropy, Shannon's information
entropy: H(P) = -Sigma_i { P_i log P_i }, where Sigma_i denotes summation
over the ith observations. So this says that information is basically the
negative of an entropy-like quantity. 

HOWEVER, it's not exactly the same as -entropy  in physics, because this
formulation includes some specific assumptions that are not required in
physics. For example, Shannon was dealing with transmission of signals
through phone lines or something, and so was mainly concerned with the
_coding_ and _decoding_ of information. Thus, the Shannon information
requires that there be a sender and a receiver, and that both of these
parties speak the same language and have access to the same dictionary
and vocabulary. Also, the Shannon information is explicitly considering
an input-transmission line-output situation. Neither of these conditions
are required in calculating the physical entropies of substances. 

So the Shannon information entropy is very useful in trying to understand
how neurons "encode", "transmit" and "decode" a sensory phenomenon, for
example, or maybe how morphology is "encoded" in DNA and "decoded" by
transcription and translation. But as for establishing an absolute
Shannon information content of a rock or an organism per se, I don't
think it necessarily applies. 

But I could be wrong.

Cheers

Matt

From owner-biophysics@net.bio.net Wed Nov 12 22:00:00 1997
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From: fujimoto@u.washington.edu (Bryant Fujimoto)
Newsgroups: bionet.biophysics
Subject: Re: entropy (Pentcho Valev)
Date: 13 Nov 1997 21:35:55 GMT
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<RUMYM@BGEARN.ACAD.BG> writes:

>Marc Roussel wrote:
>Delta G = Delta G0 + RT ln(Q) is not a fact independent of the second<
>law.  Furthermore, using Delta G can only be used as a criterion of<
>spontaneity under particular conditions (constant T and P).  The second<
>law is much more general than that.<

>Marc, I believe I have proved the following two things:

>1. If the second law is correct, delta G for a spontaneous reaction, at
>constant T and P, is negative.

>2. If the second law is not correct, delta G for a spontaneous reaction,
>at constant T and P, is also negative.

>Please tell me whether you accept these two statements. If not, what in
>my proof do you find wrong? If yes, would you mind if I describe the
>implications? They are very interesting.

Pentcho
  Your second statement is not correct.  In your attempt to demonstrate
it, you made two substitutions,
     -RT ln(Keq) = Delta G0
and
     Delta G0 + RT ln(Q) = Delta G

However, these are only true if thermodynamics is correct.

Regards
Bryant Fujimoto

From owner-biophysics@net.bio.net Wed Nov 12 22:00:00 1997
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From: Marc Roussel <roussel@henri.chem.uleth.ca>
Newsgroups: bionet.biophysics
Subject: Re: Beer Theories
Date: Thu, 13 Nov 1997 14:15:10 -0700
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Matt Jones wrote:
> 1) Why are there bubbles at all? Why doesn't the CO2 just stay equally
> distributed throughout the solution?

The CO2 bubbles form because the solution (beer) is out of equilibrium: 
At atmospheric pressure, you simply can't dissolve as much CO2 in water
as is present in beer.  I know this sounds a bit trite, but the
questions you're asking is analogous to asking why ice melts above 0
degrees Celcius.  It's out of equilibrium with its surroundings, and
that's about all the answer we can give.

> 2)      Why do the bubbles form on the glass surfaces, instead of just
> spontaneoulsy occuring anywhere in solution (you may need to crack
> open a frosty one and experiment to prove to yourself that this is
> actually the case. Go ahaead, I'll wait.)?

     Forming a bubble isn't easy.  Surface tension causes the bubble to
squeeze in on itself.  In fact, really tiny bubbles are normally
unstable so it's hard to get a bubble started at all.
     Bubble formation is normally nucleated:  Bubbles form near tiny
imperfections in your glass.  If you had a perfectly smooth glass, you
wouldn't get as many bubbles.  We have this kind of problem in Chemistry
labs because our glassware is normally highly polished.  When we're
boiling a liquid, we often throw in boiling chips, which are essentially
little porous rocks which facilitate bubble formation.  Otherwise, you
sometimes get "bumping", a nasty little phenomenon in which your usual
smooth boil is replaced by irregular formation of really large bubbles. 
These tend to throw a lot of hot solvent around when they break the
surface, so this is considered undesirable.
     If you're interested in this stuff, get a copy of Marion and
Hornyak's introductory Physics book.  They have a really neat section on
surface science and bubble physics.


				Marc R. Roussel
				(roussel@uleth.ca)
				Department of Chemistry and Biochemistry
				University of Lethbridge

From owner-biophysics@net.bio.net Wed Nov 12 22:00:00 1997
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From: Marc Roussel <roussel@henri.chem.uleth.ca>
Newsgroups: bionet.biophysics
Subject: Re: entropy (Pentcho Valev)
Date: Thu, 13 Nov 1997 15:24:42 -0700
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RUMYM@BGEARN.ACAD.BG wrote:
> 
> Marc Roussel wrote:
> Delta G = Delta G0 + RT ln(Q) is not a fact independent of the second<
> law.  Furthermore, using Delta G can only be used as a criterion of<
> spontaneity under particular conditions (constant T and P).  The
> second law is much more general than that.<
> 
> Marc, I believe I have proved the following two things:
> 
> 1. If the second law is correct, delta G for a spontaneous reaction,
> at constant T and P, is negative.
> 
> 2. If the second law is not correct, delta G for a spontaneous
> reaction, at constant T and P, is also negative.
> 
> Please tell me whether you accept these two statements.

I do agree with these statements because, as your derivation shows, they
are tautologies.  If Delta G, Delta G0, Q and K are given their
conventional meanings, then Delta G = Delta G0 + RT ln(Q) < 0 for a
spontaneous process necessarily follows.  However, thermodynamics goes a
good deal farther than that by telling us that G is in fact related to
two other state functions, namely H and S.  That the state function G =
H - TS has the property Delta G < 0 for a spontaneous process is a
consequence of the second law of thermodynamics.  Your derivation shows
that such a function exists.  The second law tells us what that function
should be.

				Marc R. Roussel
				(roussel@uleth.ca)
				Department of Chemistry and Biochemistry
				University of Lethbridge

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Path: biosci!daresbury!not-for-mail
From: <RUMYM@BGEARN.ACAD.BG>
Newsgroups: bionet.biophysics
Subject: The delta G problem (Pentcho Valev)
Date: 14 Nov 1997 12:30:16 -0000
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In reply to Marc Roussel and Bryant Fujimoto

I would propose a way to solve the delta G problem, but am not sure if
it would by found interesting. (Maybe nobody believes that there is a
problem at all).
   The point is to find the physical meaning of

       -RTlnK  +  RTln((B)/(A))                          /1/

Let us assume that, apart from the original system in which the reaction
A -> B occurs, there is another system in which the same reaction is at
equilibrium. A reversible conversion of one mole A into B can occur along
the following path:

1. One mole A is transported, reversibly, from the original system to the
equilibrium system (one should only use Henry's law and the ideal gas law).

2. In the equilibrium system, the mole A is converted into B.

3. One mole B is transported, reversibly, from the equilibrium system to
the original system.

Calculations show that the work extracted from the whole process is

    Wt =  -(-RTlnK  +  RTln((B)/(A)))                      /2/

where the subscript t refers to TRANSPORTATION, i.e. it is work done
while the mole is transported, outside both systems.
   I believe this is a promising starting point, but yet the subsequent
analysis is complicated, so I must be sure that people are interested.

Best regards,
Pentcho

From owner-biophysics@net.bio.net Thu Nov 13 22:00:00 1997
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From: szia@hanga.enzim.hu (Andras Szilagyi)
Newsgroups: bionet.biophysics
Subject: Re: entropy.
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On Thu, 13 Nov 1997 14:22:27 +0200, Jonathan B. Marder
<marder@agri.huji.ac.il> wrote:

>Let's just take those 5 litres of blood in the human body and consider
>the
>possible microstates which are still compatible with it remaining blood!
>I would
>bet that this is orders of magnitude higher than the possible
>microstates
>which can form in an equivalent mass of rock

Are you sure? A rock can take any shape as well, while remaining a rock
(although it's harder to change its shape than that of blood). You can
put any molecule in the rock anywhere you want, however, you can't do the
same to red blood cells.



From owner-biophysics@net.bio.net Thu Nov 13 22:00:00 1997
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From: szia@hanga.enzim.hu (Andras Szilagyi)
Newsgroups: bionet.biophysics
Subject: Re: Boltzmann's and thermodynamic entropy do not coincide (Pentcho)
Date: 14 Nov 1997 15:18:24 GMT
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On 13 Nov 1997 16:03:25 -0000, RUMYM@BGEARN.ACAD.BG
<RUMYM@BGEARN.ACAD.BG> wrote:

>
>         I            I               I
>
>         I            I               I
>
>         I---------piston-------------I
>
>         I                            I
>
>         Imembrane permeable only to DI
>
>         I                            I
>
>         I      A + B = C + D         I
>
>         I----------------------------I
>
>    One of the walls of the chamber in which the gas reaction A + B = C + D
>occurs is a membrane permeable only to D, and there is a piston behind the
>membrane. The reaction is strongly exothermic so that, in a REVERSIBLE
>ISOTHERMAL expansion of D, heat is released by the system. (In other words,
>the exothermic heat is greater than the work done as the piston is pushed).
>   It follows directly from the last assumption that, as the reaction
>proceeds, the thermodynamic entropy of the system DECREASES. (This still
>does not violate the second law - the entropy of the surroundings increases
>of course). On the other hand, this course of the reaction (comprising
>expansion of D) can also be spontaneous, i.e. it is a movement towards
>a more probable state - Boltzmann's entropy INCREASES.
>   I hope the proof is obvious and satisfactory.

No, that's not clear to me. In which direction does the piston move? Is
it moved from outside or the gas moves it? What is the role of the
membrane (what if there is no membrane)? How you calculate the
probability? Besides, a reversible process is never spontaneous --
spontaneous means irreversible; so your use of terms is confusing.

Please give a more detailed analysis, with calculations and derivations.
I don't have the reference you gave.

Andras Szilagyi


From owner-biophysics@net.bio.net Thu Nov 13 22:00:00 1997
Path: biosci!daresbury!not-for-mail
From: <RUMYM@BGEARN.ACAD.BG>
Newsgroups: bionet.biophysics
Subject: Boltzmann's versus thermodynamic entropy (Pentcho Valev)
Date: 14 Nov 1997 13:33:47 -0000
Lines: 48
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Bryant Fujimoto wrote:
  Your initial condition involves some (unstated) initial concentrations<
of the reactants and products.  As the piston behind the membrane is<
moved back, the reaction proceeds to products, and D leaves the reaction<
chamber.  At the end, the reaction chamber will contain C and only a<
very small quantity of D.  Are you really sure the entropy of the<
reaction chamber hasn't gone down?<
  The problem is that you haven't given any details.  What are<
A, B, C and D?  What are the initial and final concentrations?  Just how<
much heat leaves the reaction chamber?  (Are you sure you understand<
what reversible means in the context of the second law?)<

Bryant, the system is sufficiently defined. Initially, the reaction is at
equilibrium, and, by a small reversible movement of the piston, heat is
released (since the exothermic heat is, by definition, greater than the
work done).
   Years ago I had a one year dispute with two referees from J.Phys.Chem.
They did not find that the system is not defined. Rather, the argument was
about the following.
   I claimed that the following cycle violates the second law:

1. (Small) reversible ADIABATIC expansion. The temperature of the system
increases and the system does work.

2. The contact with the surroundings is restored isochorically. The initial
temperature is restored.

3. Reversible ISOTHERMAL compression. Work is done on the system.

I claimed that the work in step 1 is greater than that in step 3. The
referees objected that I had not proved this. So this is the real problem -
maybe unsuitable for discussion here.

  One more thing, it is possible to determine the entropy of a system<
at temperature T if you know the heat capacity at constant pressure as a<
function of temperature from near 0K to T, and also Delta H for any<
phase transitions between 0K and T.  This isn't known for many systems,<
but for the few that it is, the calcuation can be down and it agrees to <
within experimental error with the results of statistical mechanics.<

   I am not sure what you are driving at, but I have never rejected anything
"in general" - I have always tried to be concrete. I do not even reject the
delta G presentation of chemical work "in general" - on the contrary,
the most important work done in biosystems - that done by the transmembrane
pH gradient, is suitably described by delta G.

Best regards,
Pentcho

From owner-biophysics@net.bio.net Thu Nov 13 22:00:00 1997
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From: <RUMYM@BGEARN.ACAD.BG>
Newsgroups: bionet.biophysics
Subject: Boltzmann's versus thermodynamic entropy (Pentcho Valev)
Date: 14 Nov 1997 18:29:21 -0000
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Andras Szilagyi wrote:
No, that's not clear to me. In which direction does the piston move? Is<
it moved from outside or the gas moves it? What is the role of the<
membrane (what if there is no membrane)? How you calculate the<
probability? Besides, a reversible process is never spontaneous --<
spontaneous means irreversible; so your use of terms is confusing.<

Please give a more detailed analysis, with calculations and derivations.<
I don't have the reference you gave.<

Andras, I am the only one who tries to present
rigorous analysis, but this possibility is limited, especially in an
e-mail discussion. Moreover, the proof in this case does not require
"calculations and derivations" - the qualitative picture is enough.
Maybe I should only have given the formula

     Q(released) = Q(produced) - P(delta V)                  /1/

where Q(released) is the heat released by the system as D has undergone
a small isothermal reversible expansion, Q(produced) is the heat
produced by the reacting molecules inside the system, P is the pressure
of D and delta V is the change of volume of D.
   I speak of EXPANSION of D, so this determines the direction of the
piston. Similarly to CO2 expansion as the beer bottle is open, the
expansion of D (reversible in this case) drives the reaction (exothermic
in this case) towards the products. In other words, it is the gas D that
moves the piston, but a slightly weaker force is applied on the other
side of the piston.
   The role of the membrane is to let only D pass. If there were no membrane,
the whole system would expand - there would be no chemical reaction - only
a mixture of gases would expand.
   There is no need to calculate the probability (I am not sure if it is
possible at all). There can be no doubt that in any spontaneous process
the system moves towards a more probable state.
   Maybe my use of the terms "spontaneous" and "reversible" is confusing,
but still I am using a well established procedure in thermodynamics. We
want to determine the entropy change for a spontaneous process - in this
case a spontaneous expansion of D (combined with the chemical reaction
of course) between two equilibrium states of the system characterised by
volumes of D  V1 and V2  (V1 < V2). For this purpose, we perform the
respective REVERSIBLE transition between the two states. As the reversible
version is isothermal, the only thing that matters is whether the system
absorbs or releases heat. If it absorbes heat, the entropy of the system
INCREASES. If it releases heat, the entropy DECREASES. As in this case
a lot of heat is produced inside the system but less work is done, the
system as a whole RELEASES heat and its thermodynamic entropy DECREASES.
   So we essentially analyse the SPONTANEOUS process (the reversible
version is used only to determine the thermodynamic entropy). However
any spontaneous process is a movement towards a more probable state -
this means that Boltzmann's entropy INCREASES. (By the way, it is
Boltzmann's entropy that each participant in this discussion has in mind).

Best regards,
Pentcho

From owner-biophysics@net.bio.net Thu Nov 13 22:00:00 1997
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From: szia@hanga.enzim.hu (Andras Szilagyi)
Newsgroups: bionet.biophysics
Subject: Re: entropy.
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Don Bashford wrote in message ...
>szia@hanga.enzim.hu (Andras Szilagyi) writes:
>
>> That is, what we should compare is the number of ways you can arrange
>>the
> atoms of a rock to obtain a rock vs. the number of ways you can
>>arrange
>> the atoms of a living organism to obtain that living organism....
>
>Not fair!  You allow the rock's atoms any arrangement the forms "A
rock",
>while the organism's atoms must form "THAT living organism".  It's as
>if you want to compare a one-gram insect with with a gram of some
>freely morphing "rock" system that is actually an equilibrium ensemble
of all
>possible "rocks" composed of a given number and type of atoms.
>
>How about comparing a one-gram insect with a single one-gram crystal?

Right. The basic question is: what is a macroscopic state? I always felt
that "macroscopic state" is somewhat ill-defined in thermodynamics, at
least it's not always easy to tell what a macroscopic state is. I think
that we should consider macroscopic states as arbitrarily defined sets of
microscopic states. Let's take an insect, for example. If we take all
possible configurations of the atoms of the insect then it's only a very
small region of the configuration space in which the system can be called
an insect. But "insect" is not a thermodynamically defined set of
microstates, it's only a human concept. But if I want to know the entropy
of the insect, I should count those microstates, and should not count all
other states that make up e.g. a mouse, a handful of grass, etc.,
although thermodynamically those all may be equivalent. And it's still
valid to speak of the entropy of the insect since an insect is a very
stable thing, it's in steady-state; it definitely has an entropy.

It's a good question about the rock. What is the set of microstates that
comprise a single and same rock? If we take the human concept of "rock"
then the shape and the arrangement of the atoms in the rock does not
matter until that piece of material remains a rock. But the rock will not
necessarily try all those microstates in reality.

An insect does not appear to be a very ordered thing at a first glance; a
crystal seems to be much more ordered. An insect is a mixture of a great
number of various substances after all; one may think that its entropy
could be decreased by simply separating all those substances. Pure
substances have lower entropies because we have no mixing entropy.

But that's a false reasoning. In a real mixture, all molecules of all
components are allowed to move freely in the total volume of the system.
That is not allowable in an insect, however. If all molecules of it could
move freely then it would be a homogeneous mass of organic substance, not
an insect. Thus, an insect is definitely not a mixture in the
thermodynamic sense of the word; and actually it is a very ordered
system. And you can't separate all its components because it's no longer
an insect then.

By the way, the comparison of the entropy of an insect and a rock is also
problematic because an insect is a steady-state system that is very far
from equilibrium, producing entropy all the time, while a rock is usually
an equilibrium system. A rock (or a crystal) could also be moved away
from equilibrium, and its entropy would decrease then. By moving it
further away from equilibrium (entropy decreases further), at a point it
could become an insect. So my impression is that the insect must have
lower entropy than the rock.

Any comments are welcome.

Andras Szilagyi


From owner-biophysics@net.bio.net Sat Nov 15 22:00:00 1997
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Well COP theory at http://www.enticypress.com should interest you.
It at least suggest support for your approach.  You should find
this interesting.  In the perfume industry after smelling three perfumes
your ability to chose a good perfume for your self or some one else
approaches zero.  When you mix perfumes together they stink.
Coffee odor from a fresh coffee can will reset the sensory registors.
I suspect that coffee might help in sports science.
Ron Blue

----------
From: 	Sharon Carlin
Sent: 	Saturday, November 15, 1997 8:14 PM
To: 	biophys@net.bio.net
Subject: 	application of aromatherapy to sports science.

I am preparing a dissertation on the application of aromatherapy to
sports science.

Has anyone any experience of using aromatherapy to aid sports
performance or training ??

Any information on people or institutions involved in research in this
field would be very much appreciated.

please reply by email ( n9560593@wlv.ac.uk )

thank you all

Sharon






From owner-biophysics@net.bio.net Sat Nov 15 22:00:00 1997
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From: n9560593@wlv.ac.uk (Sharon Carlin)
Newsgroups: bionet.biophysics
Subject: application of aromatherapy to sports science.
Date: Sun, 16 Nov 1997 01:14:15 GMT
Organization: University of Wolverhampton 
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I am preparing a dissertation on the application of aromatherapy to
sports science.

Has anyone any experience of using aromatherapy to aid sports
performance or training ??

Any information on people or institutions involved in research in this
field would be very much appreciated.

please reply by email ( n9560593@wlv.ac.uk )

thank you all

Sharon


From owner-biophysics@net.bio.net Sat Nov 15 22:00:00 1997
Path: biosci!daresbury!uninett.no!newscore.univie.ac.at!news.iif.hu!szia
From: szia@hanga.enzim.hu (Andras Szilagyi)
Newsgroups: bionet.biophysics
Subject: Re: Boltzmann's versus thermodynamic entropy (Pentcho Valev)
Date: 16 Nov 1997 12:22:31 GMT
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Thank you, Pentcho, for the description. I think I understand the
problem now. However, I think that you are wrong in your
conclusion.

The first part of your analysis, regarding thermodynamic entropy,
seems to be correct. The thermodynamic entropy of the system
decreases during the process.

You then say that this process is spontaneous so the probability
(and, consequently, the Boltzmann entropy) increases during the
process. Now that's where you are wrong in my opinion.

As I understand from your description, this process is an isothermal
process. The spontaneity criterion for an isothermal process is not
deltaS > 0, as you imply, but deltaF < 0 where F=E-TS is the free energy
of the system (or, if the pressure is held constant too then the
criterion is deltaG < 0 where G=H-TS is the Gibbs free energy). In the
process in question, entropy decreases, but the internal energy E
decreases too (recall that an exothermic chemical reaction occurs) so
that deltaF (or deltaG) will be negative. Therefore, at the end of the
process, you have fewer "energy packets" to distribute between the
particles/energy levels of the system, and the number of microscopic
states (which is equivalent to thermodynamic probability) will be
smaller. So the probability will decrease and not increase as you assert,
and obviously the same is true for the Boltzmann entropy. Of course, this
is compensated for by the increase of the thermodynamic probability of
the environment. [S(total)=S(system)+S(environment), and that is
equivalent with W(total)=W(system)*W(environment) where W=exp(S/k) is the
thermodynamic probability.] So the _total_ probability will increase
(that's why the process is spontaneous), but the probability of the
system itself will _decrease_ in the process. Are you surprised?

I am afraid that you did not manage to overthrow thermodynamics
this time. :-)

Andras Szilagyi


From owner-biophysics@net.bio.net Sun Nov 16 22:00:00 1997
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From: ISAAC FORQUER <s001ipf@discover.wright.edu>
Newsgroups: bionet.biophysics
Subject: Re: Beer Theories
Date: Sun, 16 Nov 1997 23:57:34 -0500
Organization: Wright State University
Lines: 28
Message-ID: <Pine.SUN.3.93.971116235454.21004B-100000@discover.wright.edu>
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To the interested beer theorists,

My bite:	I think the only covalent thing that could be going on is
the acid-base chemistry going on between CO2 and the beer.  I forget how
that works, so don't quote me, but wouldn't the out gassing of the CO2
when you open increase the pH slightly because of the decrease in CO2
concentration???

***********************************************************************
Isaac Forquer
Wright State University
Dept. of Biological Sciences
Dayton, OHIO 45435

Home address:
4954 Woodman Pk. Dr. Apt. 16
Dayton, OH 45429

(937)-258-3329

My take off of the great E. J. Rutherford:

"All of biology is photosynthesis, the rest is just stamp collecting"


***You best teach what you most need to learn***
***********************************************************************


From owner-biophysics@net.bio.net Sun Nov 16 22:00:00 1997
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From: yummyone@webtv.net (Annie Whey)
Newsgroups: bionet.biophysics
Subject: Re: rock - living organism comparison  (Pentcho Valev)
Date: Mon, 17 Nov 1997 01:49:49 -0600
Organization: WebTV Subscriber
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iptsg.epfl.ch/aps/BAPSGEC97/abs/5900002.html

Theophrastus Bomblastus

From owner-biophysics@net.bio.net Sun Nov 16 22:00:00 1997
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From: lukasz@wlheye.jsei.ucla.edu (Lukasz Salwinski)
Newsgroups: bionet.biophysics
Subject: Re: Boltzmann versus thermodynamic entropy (Pentcho Valev)
Date: 17 Nov 1997 21:35:22 GMT
Organization: Jules Stein Eye Institute, UCLA
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-- 

>>>PROCESS BETWEEN TWO EQUILIBRIUM STATES, THE SYSTEM GOES TOWARDS THE MORE
>>>PROBABLE ONE. You can find this
>>
>>
>>beep! wrong!  not THE SYSTEM but THE ISOLATED SYSTEM.
>>
>>if the system is interacting with environment (as is the case of an
>>isothermic process) the environment is 'selecting' the states according to
>>some criterium. an analogy is tossing a coin but showing it to audience
>>only if it's tails. probability of getting tails is 1/2 if the system(=coin)
>>do not interact with the environment(=experimentator's 'censorship'). if
>>there's interaction the probability of tails can be 1.
>>
>>
>>>But is not this an absurdity?
>>
>>nothing absurd about that.
>>
>>lukasz
> A spontaneous process between two equilibrium states is an oxymoron if
>ever there was one. An equilibrium state is the highest entropy state


ok ;o)  take away EQUILIBRIUM from Pentcho's statement... 


lukasz

From owner-biophysics@net.bio.net Sun Nov 16 22:00:00 1997
Path: biosci!BUPHYC.BU.EDU!bc
From: bc@BUPHYC.BU.EDU (Bernard Chasan)
Newsgroups: bionet.biophysics
Subject: Re: Boltzmann versus thermodynamic entropy (Pentcho Valev)
Date: 17 Nov 1997 12:55:47 -0800
Organization: BIOSCI International Newsgroups for Molecular Biology
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>--
>
>>(probability) and thermo entropy, we need to define them SEPARATELY. The
>>only reliable definition of probability I know of is: IN A SPONTANEOUS
>>PROCESS BETWEEN TWO EQUILIBRIUM STATES, THE SYSTEM GOES TOWARDS THE MORE
>>PROBABLE ONE. You can find this
>
>
>beep! wrong!  not THE SYSTEM but THE ISOLATED SYSTEM.
>
>if the system is interacting with environment (as is the case of an
>isothermic process) the environment is 'selecting' the states according to
>some criterium. an analogy is tossing a coin but showing it to audience
>only if it's tails. probability of getting tails is 1/2 if the system(=coin)
>do not interact with the environment(=experimentator's 'censorship'). if
>there's interaction the probability of tails can be 1.
>
>
>>But is not this an absurdity?
>
>nothing absurd about that.
>
>lukasz
 A spontaneous process between two equilibrium states is an oxymoron if
ever there was one. An equilibrium state is the highest entropy state
consistent with constraints. An example of a constraint is a partition
between two halves of a box, where one half contains molecules, the other
half does not. Now remove the partition and a new equilibrium is attained
after some relaxation time. In that state molecules are uniformly
distributed throughout the box, and the number of states accessible to the
molecules has gone up astronomically. There are not two choices of
equilibrium - just one state with maximum possible entropy.
BC

Professor Bernard Chasan
Physics Department, Boston University
 Boston MA 02215
(617) 353-2608



From owner-biophysics@net.bio.net Sun Nov 16 22:00:00 1997
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From: lukasz@wlheye.jsei.ucla.edu (Lukasz Salwinski)
Newsgroups: bionet.biophysics
Subject: Re: Boltzmann versus thermodynamic entropy (Pentcho Valev)
Date: 17 Nov 1997 16:16:18 GMT
Organization: Jules Stein Eye Institute, UCLA
Lines: 28
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Message-ID: <64pqki$1tpq@uni.library.ucla.edu>
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NNTP-Posting-Host: wlheye.jsei.ucla.edu


-- 

>(probability) and thermo entropy, we need to define them SEPARATELY. The
>only reliable definition of probability I know of is: IN A SPONTANEOUS
>PROCESS BETWEEN TWO EQUILIBRIUM STATES, THE SYSTEM GOES TOWARDS THE MORE
>PROBABLE ONE. You can find this


beep! wrong!  not THE SYSTEM but THE ISOLATED SYSTEM. 

if the system is interacting with environment (as is the case of an 
isothermic process) the environment is 'selecting' the states according to 
some criterium. an analogy is tossing a coin but showing it to audience 
only if it's tails. probability of getting tails is 1/2 if the system(=coin) 
do not interact with the environment(=experimentator's 'censorship'). if
there's interaction the probability of tails can be 1.


>But is not this an absurdity?

nothing absurd about that. 

lukasz





From owner-biophysics@net.bio.net Sun Nov 16 22:00:00 1997
Path: biosci!internet!biosci!not-for-mail
From: biohelp (BIOSCI Administrator)
Newsgroups: bionet.biophysics
Subject: BIOSCI/bionet miniFAQ & Fundraiser
Date: 17 Nov 1997 02:00:08 -0800
Organization: BIOSCI International Newsgroups for Molecular Biology
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(LAST REVISION: 30-JUL-95)

This BIOSCI "miniFAQ" is designed to answer the questions that come up
the *most frequently*.  The main BIOSCI FAQ (Frequently Asked
Questions) is accessible on the World Wide Web at URL
http://www.bio.net/.

If you can not find an answer to your question in this or other
documentation, the BIOSCI technical support staff answers e-mail
queries sent to

		       biosci-help@net.bio.net

We can only answer questions about the use of the newsgroups and
mailing lists.  We unfortunately do not have the staff to do Internet
information searches or answer scientific questions.  Please post
those to the appropriate BIOSCI/bionet newsgroups.


	Contents:
	--------
	0) BIOSCI NEEDS YOUR SUPPORT!!

	1) Using the WWW to access the BIOSCI/bionet newsgroups.

	2) What to do about "spams," i.e., junk mail, ads, etc.

	3) Examples of subscribing and unsubscribing to the mailing lists.

	4) The BIOSCI user address and research interest directory.


0) BIOSCI NEEDS YOUR SUPPORT!!
------------------------------
BIOSCI's government funding has been expended, and we are now
operating solely from advertising revenue that we have raised from our
Web site at http://www.bio.net/.  We need just a few minutes of your
time to help us serve you.

You can do two important things which will take very little time for
you individually and will immensely help us continue to help you.

First, please use our WWW system at http://www.bio.net/ to access the
archives.  You can post or reply to messages via your Web browser as
described in item #1 below.  Your usage helps attract sponsors. If you
contact any of our sponsors, please be sure to thank them for
supporting BIOSCI. It is critical for them to get this feedback if
they are to continue their sponsorship for the long term.

Second, if you work for a company or organization that provides
products or services of interest to the biology community, please pass
this message on to your marketing or marketing communications
department or other appropriate group.  Please ask them to help
support BIOSCI by sponsoring our Web site and explain the uses and
benefits of the system to the biology community. If they are
interested, they can then contact us for further information at our
tech support address, biosci-help@net.bio.net.


1) Using the WWW to access the BIOSCI/bionet newsgroups.
--------------------------------------------------------
As of 10 December 1995, all BIOSCI/bionet full newsgroups are
accessible through the World Wide Web (WWW) at URL http://www.bio.net.
One can read and reply publicly or privately to both recent postings
and archived messages through one's Web browser if it is configured
properly to send e-mail.  Each newsgroup is equipped with its own WAIS
index.  The main BIOSCI home page also has access to the BIO-JOURNALS
Table of Contents database WAIS index and the BIOSCI user address
database described in another item further below.


2) What to do about "spams," i.e., junk mail, ads, etc.
-------------------------------------------------------
BIOSCI is a set of parallel USENET newsgroups (the "bionet" groups),
mailing lists, and a hypermail archive at URL http://www.bio.net/.
The same postings are distributed on all media (except for a small
number of mailing-list-only groups at net.bio.net).  Unfortunately it
is becoming a despicable practice on the Internet (by a few people out
to make a fast buck) to do automated mass postings to thousands of
newsgroups and mailing lists.  These attempts to grab free advertising
are refered to as "spams" in the usual, somewhat boneheaded, net
terminology.  USENET is more susceptible to this practice, and many
spams originate on the USENET groups and then are passed on to the
mailing lists.  However, spammers also get lists of mailing addresses
and hit these too, so neither medium is immune.

What should you do personally if you get junk mail?
---------------------------------------------------
Just delete it and move on without reading it further.  Filing a
protest is becoming increasingly useless because spammers are often
disguising the addresses where the messages are sent from.  Unless you
really understand Internet mail systems, your attempt at protest by
sending replies to the message will often end up being sent to the
address of an innocent person that the spammer is victimizing.

What can BIOSCI/bionet do to protect its newsgroups?
----------------------------------------------------
The only solution currently available is to moderate the newsgroup.
If this newsgroup is already moderated, then you are in good shape.
Moderation protects the USENET distribution from about 95% of the
spams that are being sent to date and protects the mailing lists
completely.  Moderation means, however, that someone has to take the
time to review each message before it goes out.  We have set up
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This takes no more time than that needed to read the message and pass
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Most newsgroups currently have a discussion leader who is responsible
for their newsgroup.  The discussions leaders and their e-mail
addresses are listed in the BIOSCI Information Sheet which is
available on the Web at http://www.bio.net/.  If a newsgroup is being
hit with too many junk postings, please contact the discussion leader
for that group and see if there is interest in moderating the group.
Please do not assume that by simply posting a complaint to the
newsgroup itself, anyone on the BIOSCI staff will act on your
complaint.  With close to 100 newsgroups to run, the BIOSCI staff has
to rely on the discussion leaders of each newsgroup to report problems
directly to us at biosci-help@net.bio.net.

We will moderate any of our newsgroups if the discussion leader tells
us that the readership of the group wishes to do so and if a moderator
is willing to do the work.  For most BIOSCI/bionet groups, this
entails only a few minutes of work each day.

Moderating a newsgroup will resolve probably 95% of the junk postings
on the USENET distribution.  Unfortunately there are easy ways for
determined spammers to override the moderation mechanism on USENET,
but we can protect our e-mail subscribers from unwanted postings if
the newsgroup is moderated.  You can also access our newsgroups over
the WWW at URL http://www.bio.net.  While this Web interface will not
stop spammers from trying to post to the groups, this will give you
yet another way, besides using USENET news, to keep the junk out of
your personal mail files.  For those of you with local USENET news
systems, the Web interface will also give you faster access to new
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3) Examples of subscribing and unsubscribing to the mailing lists.
------------------------------------------------------------------
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Gory details are in the BIOSCI Information sheets on the Web at
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Users in the Americas and Pacific Rim countries who use the BIOSCI
------------------------------------------------------------------
node at computer net.bio.net:
----------------------------

A) Determine the "listname" which is the <=8 character mail address
                                         ^^^^^^^^^^^^^
   for the group.  These can be found in the BIOSCI Info. Sheet.  For
   the METHODS-AND-REAGENTS group the mailing address is
   methods@net.bio.net.  The listname is the portion of the address to
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B) Mail all commands in the body of a mail message addressed to
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Users in Europe, Africa, and Central Asia who use the BIOSCI node at
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To subscribe and unsubscribe to/from the BIOSCI lists, you need to
specify the full USENET newsgroup name with "bionet-news." prepended.
The USENET newsgroup names are listed in the BIOSCI Information sheet
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the USENET newsgroup name is bionet.molbio.methds-reagnts, thus the
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Please note that if the address in the list is different than the one
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4) The BIOSCI user address and research interest directory.
-----------------------------------------------------------
Please take this opportunity to add your name, address, and research
interest information to the BIOSCI User Address Database if you have
not already done so.

You can fill out the address form directly through our Web page at URL
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The address database is reindexed nightly for WWW access (the URL is
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directory.  waismail use is described above.  You can also request a
user address form by e-mail from biosci-help@net.bio.net.

Please check your database entry from time-to-time to see if your
address information is still up-to-date.  Because of our limited
personnel resources, we ask that you resubmit a *complete* form to
revise your entry; we only replace complete entries and do not have
resources to edit old forms.


From owner-biophysics@net.bio.net Sun Nov 16 22:00:00 1997
Path: biosci!daresbury!not-for-mail
From: <RUMYM@BGEARN.ACAD.BG>
Newsgroups: bionet.biophysics
Subject: Boltzmann versus thermodynamic entropy (Pentcho Valev)
Date: 17 Nov 1997 09:43:58 -0000
Lines: 47
Sender: lpddist@mserv1.dl.ac.uk
Distribution: bionet
Message-ID: <64p3ku$8j6@mserv1.dl.ac.uk>
Original-To: biophys@dl.ac.uk

Andras Szilagyi wrote:
The first part of your analysis, regarding thermodynamic entropy,<
seems to be correct. The thermodynamic entropy of the system<
decreases during the process.<

You then say that this process is spontaneous so the probability<
(and, consequently, the Boltzmann entropy) increases during the<
process. Now that's where you are wrong in my opinion.<

As I understand from your description, this process is an isothermal<
process. The spontaneity criterion for an isothermal process is not<
deltaS > 0, as you imply, but deltaF < 0 where F=E-TS is the free energy<
of the system (or, if the pressure is held constant too then the<
criterion is deltaG < 0 where G=H-TS is the Gibbs free energy). In the<
process in question, entropy decreases, but the internal energy E<
decreases too (recall that an exothermic chemical reaction occurs) so<
that deltaF (or deltaG) will be negative. Therefore, at the end of the<
process, you have fewer "energy packets" to distribute between the<
particles/energy levels of the system, and the number of microscopic<
states (which is equivalent to thermodynamic probability) will be<
smaller. So the probability will decrease and not increase as you assert,<
and obviously the same is true for the Boltzmann entropy. Of course, this<
is compensated for by the increase of the thermodynamic probability of<
the environment. [S(total)=S(system)+S(environment), and that is<
equivalent with W(total)=W(system)*W(environment) where W=exp(S/k) is the<
thermodynamic probability.] So the _total_ probability will increase<
(that's why the process is spontaneous), but the probability of the<
system itself will _decrease_ in the process. Are you surprised?<

Yes. You have in fact DEFINED the probability by the thermodynamic entropy,
but this cannot solve any problem. In order to compare Boltzmann's entropy
(probability) and thermo entropy, we need to define them SEPARATELY. The
only reliable definition of probability I know of is: IN A SPONTANEOUS
PROCESS BETWEEN TWO EQUILIBRIUM STATES, THE SYSTEM GOES TOWARDS THE MORE
PROBABLE ONE. You can find this
explicit or implicit in any textbook. If you are right, then the following
statement should be placed in textbooks: SOME SYSTEMS SPONTANEOUSLY
APPROACH A LESS PROBABLE STATE. But is not this an absurdity?
   So let us think of an independent definition of probability. I cannot
accept your attempt to assess it in terms of "energy packets". If
statistical mechanics has given a rigorous way to calculate it, then
somebody can tell us about that and we are to adopt the method. If not,
you should accept that, among different EQUILIBRIUM states, the system
chooses the most probable one.

Best regards,
Pentcho

From owner-biophysics@net.bio.net Sun Nov 16 22:00:00 1997
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From: yummyone@webtv.net (Annie Whey)
Newsgroups: bionet.biophysics
Subject: Re: National Biotech Register(NatBio) New Service
Date: Mon, 17 Nov 1997 01:55:00 -0600
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Arcturus.mit.edu/cosmics/doc-html/cosmics.htm
l 


Theophrastus Bomblastus

From owner-biophysics@net.bio.net Sun Nov 16 22:00:00 1997
Path: biosci!webtv.net!not-for-mail
From: yummyone@webtv.net (Annie Whey)
Newsgroups: bionet.biophysics
Subject: Re: Best kept "secrets" finally exposed
Date: Mon, 17 Nov 1997 01:52:33 -0600
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Who is?  Camayoc, NEXoh Ltd, Great Britain

Ex.  x500.ksc.nasa.gov:8888/lcn%3dElectric%20
Eel  

Theophrastus Bomblastus

