Of course keep the newsgroup going....and here's a question for its
readers:
I don't have easy access to University libraries etc because if I did I
could probably look it up but my question concerns membrane transport
kinetics. In a mixed solution containing two components, A and B and an
enzyme which can convert A + B to C, the rate at which the enzyme
complex EAB forms is proportional to E*A*B - I hope I've got that bit
right. I presume this comes from considerations of collision
probabilities in a perfectly mixed compartment. What I want to know is
what would happen if the enzyme were stuck on a membrane, i.e confined
to a 2D surface but with the substrates, A + B still mixed in the bulk
solution. What would be the rate of formation of EAB be proportional
too? Would it be the same (i.e E*A*B) or different because one of the
colliding particles (E) can no longer freely diffuse in 3D?
Herbert Sauro
--
Herbert M Sauro
email: HSauro at fssc.demon.co.uk
Telephone: 0131 229 3383
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"He who cannot draw on 3000 years is living from hand to mouth" Goethe
"Ah, but a man's reach should exceed his grasp, or what's a heaven for?"
R Browning.
