Lucasz Salwinski wrote:>>>>>>>>>>>>>>>>>>>>
it was pretty clear form Athel's post no change of equilibrium constant is
possible.
but if you've got problems with your equqtions:
>Let us assume that what the second law says is correct, that the equilibrium
>concentrations have remained the same and that, for simplicity, the rate of
^^^^^^^^^^^^^^
this simplification is not
valid and
leads to utter nonsense that
followed
>the catalyzed forward reaction is determined by the first step - bonding of
>A to E. Then
>> V+ = K+(A)(E) = K-(C)(E) = V- /2/
why not valid ? - because in /2/ (B) suddenly disappeared. so according to
/2/ concentration of B can changed to anything. then, according to /2/
equilibrium
concentrations of A and C should not change. utter nonsense.<<<<<<<<<<
So you claim that the rate of the enzyme reaction
A + B + E ->
cannot be described by
V+ = K+(E)(A)
Utter nonsense? Lukasz, what are you talking about?
Best regards,
Pentcho
