Don Steiger (dons at cs.missouri.edu) wrote:
: In article <410ost$qll at nntp.crl.com> rising at crl.com (Hawley K. Rising III)
: writes:
: > Excuse me for asking this, but I assume when you say the Hamiltonian of a
: > large molecule you intend to look at the molecule as a problem in many
: degrees
: > of freedom with some constraints. Why is this necessarily integrable?
: In part the answer depends on what definition of integrable you use.
Not really, but from looking at your other responses, it may be irrelevant to
the type of modelling at hand. All definitions of integrable essentially resolve
to the problem being separable. I sort of asked the question because I was
interested in how integrability might be tested by your numerical algorithm.
: However,
: it is not hard to come up with a Hamiltonian that is not integrable under any (
: reasonable ) definition of the word integrable.
They occur with probability 1, but are frequently linearized away.
Hawley Rising
rising at a.crl.com
