molarity of HCl

Harold V. Taylor cbiei01 at uni-tuebingen.de
Mon Oct 20 17:07:37 EST 1997


RUTH MCMAHON wrote:
> 
> In my lab we cannot agree on the molarity of the following solution.
> On a bottle of concentrated HCl is the following information,
> mw = 36.36
> 1.19kg = 1L
> 37%.
>
Dear Ruth,
the correct way of calculation is:

Density = 1.19 kg/l  thus you have 1190 g per l. Of these 1190 g per
liter, 37% (or 1190 * 0.37 = 440.3 g) are HCl. By dividing 440.3 g/l of
HCl by the molecular weight of HCl (36.36 g/mol), it is possible to
calculate the molarity of your solution:  440.3 g/l / 36.36 g/mol =
12.11 mol/l.

Have fun,
-- 
Harold V. Taylor
Physiol. Chem. Institut
Hoppe-Seyler-Str. 4
D-72076 Tübingen

phone: 07071-297-3353
fax:   07071-29-3361
email: cbiei01 at uni-tuebingen.de



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