Biochemistry/metabolic regulation question
asmenendez at juno.com
Fri Feb 28 12:32:48 EST 1997
C Cantina wrote:
> I am a final year BSc student in Biochemistry, Microbiology, and Botany.
> In the course of enzyme mechanisms I encountered a problem, and do not
> seem to find the answers in the books I have consulted. Even the
> lecturer could not answer my question, so I hope that somebody out there
> might have the answer. (This question goes beyond the scope of the
> course, so I so not seek an answer to any Test/Exam question, but for my
> personal gain only!)
> The enzyme phosphoglucomutase catalyzes the following reversible
> Glucose-1-phosphate to Glucose-6-phosphate.
> This reaction proceeds only in the presence of Magnesium and
> Glucose-1,6-bisPhosphate; a phosphoryl intermediate is formed in which a
> phosphate group on a single serine residue of the enzyme is exchanged
> with substrate and Glucose-1,6-bisPhosphate.
> 1. Enz-OH + Glucose-1,6-bisPhoshate to Enz-O-Phosphate +
> Glucose-1(or -6)-Phosphate
> 2. Enz-O-Phosphate + Glucose-1-Phosphate to Glucose-1,6-bisPhosphate
> + Enz-OH
> 3. Enz-OH + Glucose-1,6-bisPhosphate to Glucose-6-Phosphate +
> Here is the question:
> Why can the enzyme in the first reaction either cleave the phosphate
> from position C1 or position C6, but in the last step of the reaction
> (3.) it only cleaves the phosphate from position C1?
> Please if any one knows where I can find the answer, or could direct me
> to it would be greatly appreciated. Please send an email to
> ccantina at iafrica.com
> One idea I have is that a sort of steric hinderance could be involved.
> As said before I cannot find it in the text books.
I am no expert in enzyme reactions but I had a thought. You mentioned
the reaction will only take place in the presence of Magnesium, which is
positively charged.Lets say that in the second reaction, when
Enz-O-Phosphate reacts with Glucose-1-phoshate to make end products
Glucose-1,6-bisphoshate and Enz-OH again, either the Glucose-1,6
bisphosphate or Enz-OH have picked up a positive charge in the
reaction. Picking up a charge from the magnesium will cause the Enz-OH
to react with only one area of the Glucose-1,6-bisphospate molecule. Do
you think this could be the possible solution?
Ann Menendez MT(ASCP)
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