Fw: can someone answer my question?

kkollins at pop3.concentric.net kkollins at pop3.concentric.net
Tue Dec 8 21:04:48 EST 1998

I stand on what I've posted. K. P. Collins

Walter Eric Johnson wrote:

> kkollins at pop3.concentric.net wrote:
> : > So if g(x)=h(x), you can define a function f(x)=g(x)-h(x).  Then those
> : > values of x for which g(x)=h(x) also result in f(x)=0.  Thus, the solutions
> : > of the equation g(x)=h(x) are the values of x for which f(x)=g(x)-h(x)=0.
> :
> : There's only one Solution to any Equation... that which Maps its entire numerical-domain.
> Nonsense.  The equation f(x)=x^2-1=0 has two solutions, not one.
> They are x=1 and x=-1.
> : It doesn't
> : matter what the books 'say"...
> Of course.  Not only do you make up your own buzzwords to try to
> bamboozle people, but you also make up your own meanings for the
> words everyone else uses.
> : all one has to do to Prove the Veracity of the One-Generalized-Solution
> : view is subject a piece-by-piece "problem-solver" to more individual instances of the Generalized
> : Solution than the piecemeal Calculator can Calculate in its piecemeal way...
> Are you absolutely positive your an expert mathematician?  I'd expect
> any expert mathematician to understand what it means to prove something.
> : > In other words, when you are solving the equation g(x)=h(x), you are
> : > finding the zeros of the function f(x)=g(x)-h(x).
> :
> : One zero does not a Solution make.
> 5 is a solution to x^2=25.  5 is a zero of f(x)=x^2-25.  Are you
> saying that 5 is not a solution to x^2=25?  Are you really, truly
> absolutely positive that you are an expert mathematician?
> (By the way, x^2 means x squared.)
> Eric Johnson

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