brain sizes: Einstein's and women's

Parse Tree parsetree at hotmail.com
Sun Jul 21 02:29:52 EST 2002


"Jet" <thatjetnospam at yahoo.com> wrote in message
news:3D3A61A8.93F4E326 at yahoo.com...
>
> Parse Tree wrote:
> >
> > "Jet" <thatjetnospam at yahoo.com> wrote in message
> > news:3D3A3FCE.269F3BE9 at yahoo.com...
> > >
> > > Dumbass wrote:
> > > >
> > > > "John Knight" <johnknight at usa.com> skrev i melding
> > > > news:yNm_8.12490$Fq6.1079329 at news2.west.cox.net...
> > > > > "Thalamus" <zhil at online.no> wrote in message
> > > > > news:Azf_8.897$Py1.16186 at news2.ulv.nextra.no...
> > > > > > "John Knight" <johnknight at usa.com> skrev i melding
news:nSVZ8.8881>
> > > > > >
> > > > > > John, what is the H04, that is - what is the question of H04 ?
> > > > > > I'm Norwegian, and we have other standards here.
> > > > > > This Nigger is harping on it through several posts, and if you
could
> > > > > repeat
> > > > > > the original question "What is the length..............." etc. -
so
> > I
> > > > > could
> > > > > > shut the stupid coon.
> > > > > >
> > > > > > Brian
> > > > >
> > > > > You can see the original problem at
> > http://christianparty.net/timssh04.htm
> > > > ,
> > > > > Brian, or download the scores from
> > http://christianparty.net/cisp1295.pdf
> > > > >
> > > > > This is one of the 13 multiple choice questions (ONE THIRD of that
> > test)
> > > > > where American girls scored lower than if they had just guessed.
> > > > >
> > > > > But of course the feminazis can't even figure out what this means,
so
> > > > > they're claiming that we're lying.  Maybe you can straighten them
out,
> > > > > because I sure can't.
> > > >
> > > > Ok, the problem isn't difficult.
> > > > F=ma
> > > > S=vt
> > > >
> > > > F=force - downward
> > > > m=mass
> > > > a=acceleration
> > > > v=velocity
> > > > t=time
> > > > S=Hight of fall
> > > >
> > > > I did it this way, first I said that F=2m(v/t).
> > > >
> > > > Then I converted the equation to t=sqr(mS/ma), moving the t to the
left
> > > > side, and the F (ma) to the right side.
> > > > I used both equations for the object separatly, and ended up with
the
> > same
> > > > equation t=sqr(S/a).
> > > > Sqr means square-root of the equation in the parenthesis ().
> > > > So, the resulting velocity would be the same, as the same time is
spent
> > on
> > > > the fall, and the tension would be zero.
> > > >
> > > > Brian
> > >
> > > Mensa, my big black ass. The time spent in the fall would not be the
> > > same, because the higher object started out...higher.
> >
> > As soon as the lower object hits the ground, the system is no longer
> > falling.
> >
> > The answer really should be 0.
>
> Ah...but the question was, "what is the tension in the string as the
> system falls?".

Doesn't that refer to it as the system is in the state of falling (not at
the point it is dropped, and not after it has hit the ground)?  Since they
both travel at the same speed, the tension in the string should be zero.





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