[Neuroscience] Re: Equation that explains the behaviour of a
circuit in voltage clamp
r norman
via neur-sci%40net.bio.net
(by r_s_norman from comcast.net)
Sat Apr 4 10:26:04 EST 2009
On Sat, 4 Apr 2009 02:34:37 -0700 (PDT), "Bill.Connelly"
<connelly.bill from gmail.com> wrote:
>On Apr 4, 3:32 am, r norman <r_s_nor... from comcast.net> wrote:
>
>> If you use non-step clamp voltages, you just calculate the dV/dt term
>> and subtract the capacitative component from the total current to get
>> the pure ionic component.
>
>Well this is exactly where I am stuck, how do I calculate the current
>that "crosses" the capcitor, I know its somehow proportional to the
>series resistor, the membrane capacitance and dV/dt, but exactly how,
>I'm not sure.
Icap = C dV/dt
The resistance (conductance) is not involved.
C is a constant, easily measured. V(t) is known, hence dV/dt is
known.
More information about the Neur-sci
mailing list